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4b^2-8b=44
We move all terms to the left:
4b^2-8b-(44)=0
a = 4; b = -8; c = -44;
Δ = b2-4ac
Δ = -82-4·4·(-44)
Δ = 768
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{768}=\sqrt{256*3}=\sqrt{256}*\sqrt{3}=16\sqrt{3}$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-16\sqrt{3}}{2*4}=\frac{8-16\sqrt{3}}{8} $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+16\sqrt{3}}{2*4}=\frac{8+16\sqrt{3}}{8} $
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